If it's not what You are looking for type in the equation solver your own equation and let us solve it.
11x^2-11x-12=0
a = 11; b = -11; c = -12;
Δ = b2-4ac
Δ = -112-4·11·(-12)
Δ = 649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{649}}{2*11}=\frac{11-\sqrt{649}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{649}}{2*11}=\frac{11+\sqrt{649}}{22} $
| 2x+1|=-3 | | 3n-68=65 | | -8n+2=13-39n | | 2(9x+-1)+7(x+6)=-60 | | s+31/2s+10s=55 | | 14.5=5p+2 | | 2p-13=p-8 | | 16.6x=-0.7x+8.65 | | -4x-5=x+10 | | 4/x+5/6=1 | | 4(w-8)-7=-3(-8w+9)-6w | | 3z–6=4z | | d+22=13 | | -7(6+0.25d)=49 | | 4x+3=5(2-2x) | | 28+x+7+x=180 | | 18.9x+9.06=11.7+19.5x | | 2z-10z-17z-16z=14 | | 10-3-6x+6=1 | | -2x-10=4x+8 | | x+x+7+28=180 | | 5+10p=25 | | 7g+4g-10g=15 | | (2x+14)-2(x+63)=-5 | | 2x(2)-x=0 | | -7.67+8x+3.56=7.5x-12.11 | | Z^4=-16+16i | | 4(w-8-7=-3(-8w+9)-6w | | 7(x-4)=-5(x+2)+39 | | 2.5-0.04x=-1.18 | | 5+10p=20 | | 4p-5(p=6)= |